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The reaction of aqueous $KMnO_4$ with $H_2O_2$ in acidic conditions gives:
A
$Mn^{4+}$ and $O_2$
B
$Mn^{2+}$ and $O_2$
C
$Mn^{2+}$ and $O_3$
D
$Mn^{4+}$ and $MnO_2$
Detailed Solution
$KMnO_4$ is a strong oxidising agent and oxidises $H_2O_2$ to $O_2$; in acidic medium it is itself reduced to $Mn^{2+}$.
