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Given below are two statements:
Statement I: The boiling point of hydrides of Group 16 elements follow the order $H_2O > H_2Te > H_2Se > H_2S$.
Statement II: On the basis of molecular mass, $H_2O$ is expected to have lower boiling point than the other members of the group but due to the presence of extensive H-bonding in $H_2O$, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below:
A
Statement I is true but Statement II is false.
B
Statement I is false but Statement II is true.
C
Both Statement I and Statement II are true.
D
Both Statement I and Statement II are false.
Detailed Solution
For $H_2S$, $H_2Se$ and $H_2Te$, the boiling point increases with molecular mass.
On the basis of molecular mass, $H_2O$ should have the lowest boiling point, but due to extensive intermolecular hydrogen bonding in water, $H_2O$ has the highest boiling point.
So the order $H_2O > H_2Te > H_2Se > H_2S$ is correct and the explanation is correct: both statements are true.