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Acidity of diprotic acids in aqueous solutions increases in the order:
A
$H_2S < H_2Se < H_2Te$
B
$H_2Se < H_2S < H_2Te$
C
$H_2Te < H_2S < H_2Se$
D
$H_2Se < H_2Te < H_2S$
Detailed Solution
On moving down the group the bond length increases, so the H–E bond breaks more easily and the tendency to release $H^+$ increases.
So acidity: $H_2S < H_2Se < H_2Te$
So acidity: $H_2S < H_2Se < H_2Te$
