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The Solid State
Calculations Involving Unit Cell Dimensions
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Concepts tested
- atomic radius in a bcc lattice
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2020 1 question
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An element has a body centered cubic (bcc) structure with a cell edge of 288 pm. The atomic radius is:For bcc: $\sqrt{3}a = 4r \Rightarrow r = \frac{\sqrt{3}}{4}a$ With a = 288 pm: $r = \frac{\sqrt{3}}{4} \times 288$ pm
