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Enthalpy change for decomposition (reverse) reaction
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Consider the following reaction:- $2H_2(g)+O_2(g)\rightarrow2H_2O(g)\ \Delta_rH^\circ=-483.64$ kJ. What is the enthalpy change for decomposition of one mole of water? (Choose the right option).A 120.9 kJB 241.82 kJC 18 kJD 100 kJDecomposition for 1 mole of water: $H_2O(g)\rightarrow H_2(g)+\dfrac{1}{2}O_2(g);\ \Delta H=+\dfrac{483.64}{2}=+241.82$ kJ.