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Thermodynamics
Work in Irreversible Expansion
1 question from 1 paper, each with its answer.
- question
- 1
- paper
- 1
- of Thermodynamics
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Concepts tested
- Pressure-volume work
All Questions
2004 AIPMT 1 question
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The work done during the expansion of a gas from a volume of 4 dm$^3$ to 6 dm$^3$ against a constant external pressure of 3 atm is :-For expansion against a constant external pressure: $W = -P_{ext}\Delta V$ (work done by the gas is negative in the IUPAC sign convention).
$\Delta V = 6 - 4 = 2$ dm$^3$ $= 2$ L
$W = -3$ atm $\times 2$ L $= -6$ L atm
1 L atm $= 101.3$ J
$W = -6 \times 101.3 = -607.8$ J $\approx -608$ J
So the work done is $-608$ J.