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A series R-C circuit is connected to an alternating voltage source. Consider two situations:
(a) When capacitor is air filled.
(b) When capacitor is mica filled.
Current through resistor is i and voltage across capacitor is V then:
(a) When capacitor is air filled.
(b) When capacitor is mica filled.
Current through resistor is i and voltage across capacitor is V then:
A
$V_a = V_b$
B
$V_a < V_b$
C
$V_a > V_b$
D
$i_a > i_b$
Detailed Solution
Filling with mica increases C, so $X_C = \frac{1}{\omega C}$ decreases.
With smaller $X_C$ the voltage across the capacitor decreases (and the current increases), so $V_a > V_b$.
With smaller $X_C$ the voltage across the capacitor decreases (and the current increases), so $V_a > V_b$.