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A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are:
A
300 V, 15 A
B
450 V, 15 A
C
450 V, 13.5 A
D
600 V, 15 A
Detailed Solution
$\eta = \frac{V_SI_S}{V_PI_P} \Rightarrow 0.9 = \frac{V_S(6)}{3\times10^3} \Rightarrow V_S = 450$ V
$V_PI_P = 3000$ W, so $I_P = \frac{3000}{200} = 15$ A
$V_PI_P = 3000$ W, so $I_P = \frac{3000}{200} = 15$ A