Looking for classes? Ksquare Career Institute, Bengaluru →
In an ideal transformer, the turns ratio is $\frac{N_p}{N_s} = \frac{1}{2}$. The ratio $V_s : V_p$ is equal to (the symbols carry their usual meaning):
A
1 : 1
B
1 : 4
C
1 : 2
D
2 : 1
Detailed Solution
For an ideal transformer: $\frac{N_p}{N_s} = \frac{V_p}{V_s} = \frac{1}{2}$
$\Rightarrow \frac{V_s}{V_p} = \frac{2}{1}$
$V_s : V_p = 2 : 1$