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Let $T_1$ and $T_2$ be the energy of an electron in the first and second excited states of hydrogen atom, respectively. According to the Bohr's model of an atom, the ratio $T_1:T_2$ is :
A
$9:4$
B
$1:4$
C
$4:1$
D
$4:9$
Detailed Solution
First excited state: n = 2, $T_1 = -13.6\frac{Z^2}{n^2} = -\frac{13.6}{4}$ eV
Second excited state: n = 3, $T_2 = -\frac{13.6}{9}$ eV
$T_1 : T_2 = \frac{1}{4} : \frac{1}{9} = 9 : 4$