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The total energy of an electron in the nth stationary orbit of the hydrogen atom can be obtained by
A
$E_n=-13.6\times n^2$ eV
B
$E_n=\dfrac{13.6}{n^2}$ eV
C
$E_n=\dfrac{-13.6}{n^2}$ eV
D
$E_n=\dfrac{-1.36}{n^2}$ eV
Detailed Solution
For the hydrogen atom, the total energy of the electron in the nth orbit is $E_n=\dfrac{-13.6}{n^2}$ eV.
