The total energy of an electron in the nth stationary orbit of the hydrogen atom can be obtained by

The total energy of an electron in the nth stationary orbit of the hydrogen atom can be obtained by
A $E_n=-13.6\times n^2$ eV
B $E_n=\dfrac{13.6}{n^2}$ eV
C $E_n=\dfrac{-13.6}{n^2}$ eV
D $E_n=\dfrac{-1.36}{n^2}$ eV

Detailed Solution

For the hydrogen atom, the total energy of the electron in the nth orbit is $E_n=\dfrac{-13.6}{n^2}$ eV.

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