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Three resistors having resistances $r_1$, $r_2$ and $r_3$ are connected as shown in the given circuit. The ratio $\frac{i_3}{i_1}$ of currents in terms of resistances used in the circuit is:

A
$\frac{r_2}{r_2+r_3}$
B
$\frac{r_1}{r_1+r_2}$
C
$\frac{r_2}{r_1+r_3}$
D
$\frac{r_1}{r_2+r_3}$
The answer is A.
