A charged particle having drift velocity of $7.5\times10^{-4}\ m\,s^{-1}$ in an electric field of $3\times10^{-10}\ V\,m^{-1}$, has a mobility in $m^2V^{-1}s^{-1}$ of:

A $2.5\times10^6$

B $2.5\times10^{-6}$

C $2.25\times10^{-15}$

D $2.25\times10^{15}$

The answer is A.

Solution

Mobility $\mu = \frac{v_d}{E} = \frac{7.5 \times 10^{-4}}{3 \times 10^{-10}}$ $= 2.5 \times 10^6\ m^2V^{-1}s^{-1}$

Concept mobility from drift velocity and field

130 questions from this chapter have appeared across 27 exam years.