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A 5-ampere fuse wire can withstand a maximum power of 1 watt in the circuit. The resistance of the fuse wire is :
A
5 ohm
B
0.04 ohm
C
0.2 ohm
D
0.4 ohm
Detailed Solution
Power dissipated in a resistance: $P = I^2R$
$\Rightarrow R = \dfrac{P}{I^2}$
Here $P = 1$ W and $I = 5$ A.
$R = \dfrac{1}{5^2} = \dfrac{1}{25}$
$R = 0.04\,\Omega$
$\Rightarrow R = \dfrac{P}{I^2}$
Here $P = 1$ W and $I = 5$ A.
$R = \dfrac{1}{5^2} = \dfrac{1}{25}$
$R = 0.04\,\Omega$