Solution

In steady state, no current flows through the capacitor branch (with the $5\ \Omega$ resistor in series with the $5\ \mu F$ capacitor). So current flows only through the $2\ \Omega$ and $3\ \Omega$ resistors in series with the 10 V source: $i=\dfrac{V}{R}=\dfrac{10}{2+3}=2$ A.

Concept RC circuits in steady state

Current Electricity in past papers

130 questions from this chapter have appeared across 27 exam years.