The magnitude and direction of the current in the following circuit is

A 1.5 A from B to A through E

B 0.2 A from B to A through E

C 0.5 A from A to B through E

D $\frac{5}{9}$ A from A to B through E

The answer is C.

Solution

The circuit reduces to a $10\ \Omega$ resistor with a 5 V cell, so $i=0.5\ A$.

The circuit can be redrawn as an equivalent circuit (10 Ω resistor with a 5 V cell). $\Rightarrow i=\frac{5}{10}=0.5\ A$

Concept current in a network with two cells

130 questions from this chapter have appeared across 27 exam years.