2023 Current ElectricitySeries and Parallel Combination of Resistors Easy Question 22 of 130 in Current Electricity

10 resistors, each of resistance $R$ are connected in series to a battery of emf $E$ and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased $n$ times. The value of $n$ is:

A 1000
B 10
C 100
D 1

The answer is C.

Solution

Series current is $\frac{E}{10R}$ and parallel current is $\frac{10E}{R}$; ratio is 100.

$i_{series}=\frac{E}{R_{series}}=\frac{E}{10R}$ $i_{parallel}=\frac{E}{R_{parallel}}=\frac{E}{R/10}$ $i_{parallel}=n\times i_{series}\Rightarrow\frac{10E}{R}=\frac{nE}{10R}$ $\Rightarrow n=100$

Concept current ratio parallel to series

Current Electricity in past papers

130 questions from this chapter have appeared across 27 exam years.