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Dual Nature of Radiation and Matter
Cut-off Wavelength of X-rays
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- λ_min ∝ 1/V
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2023 1 question
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The minimum wavelength of X-rays produced by an electron accelerated through a potential difference of $V$ volts is proportional to:
$eV=\frac{hc}{\lambda_{min}}$, so $\lambda_{min}\propto\frac{1}{V}$.
$eV$ = energy of electron; for minimum wavelength, maximum loss of energy: $eV=\left(\frac{hc}{\lambda}\right)$ $\lambda\propto\left(\frac{1}{V}\right)$