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The graph which shows the variation of the de Broglie wavelength ($\lambda$) of a particle and its associated momentum ($p$) is :
Detailed Solution
de Broglie wavelength $\lambda = \frac{h}{p}$, so $\lambda \propto \frac{1}{p}$
The graph of $\lambda$ vs p is a rectangular hyperbola.
[add image: $\lambda$ vs p rectangular hyperbola]