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A charge Q $\mu C$ is placed at the centre of a cube. The flux coming out from any one of its faces will be (in SI unit):
A
$\dfrac{Q}{\varepsilon_0}\times10^{-6}$
B
$\dfrac{2Q}{3\varepsilon_0}\times10^{-3}$
C
$\dfrac{Q}{6\varepsilon_0}\times10^{-3}$
D
$\dfrac{Q}{6\varepsilon_0}\times10^{-6}$
Detailed Solution
Total flux from the cube $=\dfrac{q}{\varepsilon_0}$. By symmetry, flux through any one of the 6 faces $=\dfrac{q}{6\varepsilon_0}=\dfrac{Q\times10^{-6}}{6\varepsilon_0}$.