Looking for classes? Ksquare Career Institute, Bengaluru →
The magnetic energy stored in an inductor of inductance $4\ \mu H$ carrying a current of $2\ A$ is:
A
$8\ \mu J$
B
$4\ \mu J$
C
$4\ mJ$
D
$8\ mJ$
Explanation
$U=\frac{1}{2}LI^2=8\ \mu J$.
Detailed Solution
Magnetic energy stored in an inductor $=\frac{1}{2}LI^2=\frac{1}{2}\times4\times10^{-6}\times(2)^2=8\ \mu J$