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Electromagnetic Induction
Energy Stored in an Inductor
2 questions from 2 papers, each with its answer.
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All Questions
2023 1 question
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The magnetic energy stored in an inductor of inductance $4\ \mu H$ carrying a current of $2\ A$ is:
$U=\frac{1}{2}LI^2=8\ \mu J$.
Magnetic energy stored in an inductor $=\frac{1}{2}LI^2=\frac{1}{2}\times4\times10^{-6}\times(2)^2=8\ \mu J$
2018 1 question
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The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance
$L = 2U/I^2$.
Energy stored in inductor $U = \frac{1}{2}LI^2$ $25\times10^{-3} = \frac{1}{2}\times L\times(60\times10^{-3})^2$ $L = \frac{25\times2\times10^{6}\times10^{-3}}{3600} = \frac{500}{36}$ $= 13.89$ H