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The magnetic potential energy stored in a certain inductor is 25 mJ, when the current in the inductor is 60 mA. This inductor is of inductance
Explanation
$L = 2U/I^2$.
Detailed Solution
Energy stored in inductor $U = \frac{1}{2}LI^2$
$25\times10^{-3} = \frac{1}{2}\times L\times(60\times10^{-3})^2$
$L = \frac{25\times2\times10^{6}\times10^{-3}}{3600} = \frac{500}{36}$
$= 13.89$ H