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A rectangular wire loop of sides 8 cm and 3 cm with a small cut, is moving out of a region of uniform magnetic field of magnitude 0.3 T directed normal to the plane of the loop. The emf developed across the cut, if the velocity of the loop is 2 $cm\,s^{-1}$, in a direction normal to the shorter side of the loop, will be
A
$1.8 \times 10^{-4}$ volt
B
$1.2 \times 10^{-4}$ volt
C
$1.3 \times 10^{-4}$ volt
D
$4.8 \times 10^{-4}$ volt
Detailed Solution
The loop moves normal to the shorter side (3 cm), so the side cutting the field lines has length l = 3 cm.
$e = lBv = 3 \times 10^{-2} \times 0.3 \times 2 \times 10^{-2}$
$= 1.8 \times 10^{-4}$ volt