Solution

$mg_h = \frac{mg_0}{\left(1 + \frac{h}{R}\right)^2}$ $W = \frac{72}{\left(1 + \frac{R/2}{R}\right)^2} = \frac{72}{(3/2)^2} = \frac{4}{9} \times 72 = 32$ N

Concept weight at a height above the earth

Gravitation in past papers

66 questions from this chapter have appeared across 26 exam years.