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The escape velocity of a body on the earth surface is 11.2 km/s. If the same body is projected upward with velocity 22.4 km/s, the velocity of this body at infinite distance from the centre of the earth will be:
A
$11.2\sqrt2$ km/s
B
Zero
C
11.2 km/s
D
$11.2\sqrt3$ km/s
Detailed Solution
$V_\infty=\sqrt{V^2-V_e^2}$. Given $V=2V_e$. $V_\infty=\sqrt{(2V_e)^2-V_e^2}=\sqrt{3}V_e=11.2\sqrt3$ km/s.