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If R is the radius of the earth and g is the acceleration due to gravity on the earth surface. Then the mean density of the earth will be:
A
$\dfrac{\pi RG}{12g}$
B
$\dfrac{3\pi R}{4gG}$
C
$\dfrac{3g}{4\pi RG}$
D
$\dfrac{4\pi G}{3gR}$
Detailed Solution
$g=\dfrac{4}{3}\pi GR\rho\Rightarrow\rho=\dfrac{3g}{4\pi GR}$.