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In the given (V – T) diagram, what is the relation between pressure $P_1$ and $P_2$?
A
Cannot be predicted
B
$P_2 = P_1$
C
$P_2 > P_1$
D
$P_2 < P_1$
Detailed Solution
$PV = nRT \Rightarrow V = \left(\frac{nR}{P}\right)T$, so slope $= \frac{nR}{P}$
The line for $P_2$ is steeper ($\theta_2 > \theta_1$), so $\frac{1}{P_2} > \frac{1}{P_1} \Rightarrow P_1 > P_2$
The line for $P_2$ is steeper ($\theta_2 > \theta_1$), so $\frac{1}{P_2} > \frac{1}{P_1} \Rightarrow P_1 > P_2$