2004 AIPMT Kinetic TheoryIdeal Gas Equation Easy Question 5 of 5 in Ideal Gas Equation

The equation of state for 5g of oxygen at a pressure P and temperature T, when occupying a volume V, will be :- (Where R is the gas constant.)

A PV = 5 RT
B PV = $\left(\dfrac{5}{2}\right)$ RT
C PV = $\left(\dfrac{5}{16}\right)$ RT
D PV = $\left(\dfrac{5}{32}\right)$ RT

The answer is D.

Solution

Ideal gas equation: $PV = \mu RT$, where $\mu$ is the number of moles.
Molar mass of oxygen ($O_2$) = 32 g/mol.
$\mu = \dfrac{\text{mass}}{\text{molar mass}} = \dfrac{5}{32}$ moles
$\therefore PV = \left(\dfrac{5}{32}\right)RT$

Concept Number of moles in ideal gas equation

Ideal Gas Equation in past papers

5 questions from this chapter have appeared across 5 exam years.