2023 Manipur Laws of MotionFriction on an inclined plane - limiting equilibrium Medium Question 11 of 72 in Laws of Motion

A block of mass 2 kg is placed on inclined rough surface AC (as shown in figure) of coefficient of friction $\mu$. If $g=10 m s^{-2}$, the net force (in N) on the block will be:

A $10\sqrt3$
B zero
C 10
D 20

The answer is B.

Solution

$\tan30^\circ=\dfrac{1}{\sqrt3}=\mu$. Since $\mu=\tan\theta$, the block is exactly on the verge of sliding and remains at rest (limiting friction balances the component of gravity along the incline), so the net force on it must be zero.

Concept Friction on an inclined plane - limiting equilibrium

Laws of Motion in past papers

72 questions from this chapter have appeared across 27 exam years.