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A block of mass 2 kg is placed on inclined rough surface AC (as shown in figure) of coefficient of friction $\mu=\dfrac{1}{\sqrt3}$, angle 30° with the horizontal. If $g=10\ ms^{-2}$, the net force (in N) on the block will be: [add image]
A
$10\sqrt3$
B
zero
C
10
D
20
Detailed Solution
$\tan30^\circ=\dfrac{1}{\sqrt3}=\mu$. Since $\mu=\tan\theta$, the block is exactly on the verge of sliding and remains at rest (limiting friction balances the component of gravity along the incline), so the net force on it must be zero.