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A 1 kg object strikes a wall with velocity 1 m s$^{-1}$ at an angle of $60^\circ$ with the wall and reflects at the same angle. If it remains in contact with wall for 0.1 s, then the force exerted on the wall is:-
A
$30\sqrt3$ N
B
Zero
C
$10\sqrt3$ N
D
$20\sqrt3$ N
Detailed Solution
$F=\left|\dfrac{\Delta\vec p}{\Delta t}\right|=\dfrac{2mv\sin\theta}{t}=\dfrac{2(1)(1)\sin60^\circ}{0.1}=10\sqrt3$ N.