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A block of mass m is placed on a smooth inclined wedge ABC of inclination $\theta$ as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and $\theta$ for the block to remain stationary on the wedge is


Explanation
Balance the pseudo force ma and gravity with the normal reaction: $a = g\tan\theta$.
Detailed Solution
In the non-inertial frame,
$N\sin\theta = ma$ ...(i)
$N\cos\theta = mg$ ...(ii)
$\tan\theta = \frac{a}{g}$
$a = g\tan\theta$
