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On the horizontal surface of a truck a block of mass 1 kg is placed ($\mu$ = 0.6) and truck is moving with acceleration 5 m/s$^2$ then the frictional force on block will be : -
A
5 N
B
6 N
C
5.88 N
D
8 N
Detailed Solution
In the frame of the truck, a pseudo force $F = ma = 1 \times 5 = 5$ N acts on the block backward.
Limiting (maximum) static friction: $f_L = \mu_sN = \mu_smg = 0.6 \times 1 \times 10 = 6$ N
Since $F = 5$ N $\lt f_L = 6$ N, the block does not slip; it moves with the truck.
Static friction is self-adjusting and equals the force needed: $f_r = 5$ N
So the frictional force on the block is 5 N (it is this force that gives the block its 5 m/s$^2$ acceleration).
Limiting (maximum) static friction: $f_L = \mu_sN = \mu_smg = 0.6 \times 1 \times 10 = 6$ N
Since $F = 5$ N $\lt f_L = 6$ N, the block does not slip; it moves with the truck.
Static friction is self-adjusting and equals the force needed: $f_r = 5$ N
So the frictional force on the block is 5 N (it is this force that gives the block its 5 m/s$^2$ acceleration).