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Magnetism and Matter
Magnetic Dipole Moment of a Current Loop
1 question, with its answer.
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A uniform conducting wire of length $12a$ and resistance $R$ is wound up as a current carrying coil in the shape of, (i) an equilateral triangle of side $a$. (ii) a square of side $a$. The magnetic dipole moments of the coil in each case respectively are:Wire length = 12a. (i) Equilateral triangle of side a: perimeter 3a, so number of turns = 4. $M_1 = NIA = 4 \times I \times \frac{\sqrt{3}}{4}a^2 = \sqrt{3}Ia^2$ (ii) Square of side a: perimeter 4a, so number of turns = 3. $M_2 = 3 \times I \times a^2 = 3Ia^2$
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