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A radioactive nucleus $^A_ZX$ undergoes spontaneous decay in the sequence $^A_ZX\rightarrow{}_{Z-1}B\rightarrow{}_{Z-3}C\rightarrow{}_{Z-2}D$, where $Z$ is the atomic number of element X. The possible decay particles in the sequence are:
A
$\alpha,\ \beta^+,\ \beta^-$
B
$\beta^+,\ \alpha,\ \beta^-$
C
$\beta^-,\ \alpha,\ \beta^+$
D
$\alpha,\ \beta^-,\ \beta^+$
The answer is B.