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A nucleus of mass number 189 splits into two nuclei having mass number 125 and 64. The ratio of radius of two daughter nuclei respectively is :
A
$25:16$
B
$1:1$
C
$4:5$
D
$5:4$
Detailed Solution
Nuclear radius $R = R_0A^{1/3}$
$\frac{R_{125}}{R_{64}} = \frac{R_0(125)^{1/3}}{R_0(64)^{1/3}} = \frac{5}{4}$
So the ratio is 5 : 4.
