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The radius of Germanium (Ge) nuclide is measured to be twice the radius of $^{9}_{4}Be$. The number of nucleons in Ge are :-
A
73
B
74
C
75
D
72
Detailed Solution
Nuclear radius: $R = R_0 A^{1/3}$, so $A \propto R^3$.
$\dfrac{A_{Ge}}{A_{Be}} = \left(\dfrac{R_{Ge}}{R_{Be}}\right)^3$
$\Rightarrow A_{Ge} = \left(\dfrac{R_{Ge}}{R_{Be}}\right)^3 (A_{Be}) = (2)^3 (9)$
$A_{Ge} = 8 \times 9 = 72$
So the number of nucleons in Ge is 72.
$\dfrac{A_{Ge}}{A_{Be}} = \left(\dfrac{R_{Ge}}{R_{Be}}\right)^3$
$\Rightarrow A_{Ge} = \left(\dfrac{R_{Ge}}{R_{Be}}\right)^3 (A_{Be}) = (2)^3 (9)$
$A_{Ge} = 8 \times 9 = 72$
So the number of nucleons in Ge is 72.