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Consider three media P, Q and R with refractive indices 1, 1.25 and 1.5 respectively. The medium Q having a thickness of 5 cm is placed between extended media P and R as shown in the figure. An object O is placed at the centre of medium Q. If viewed from medium P near the normal direction, the apparent depth of O is $h_1$. For similar observation from medium R, the apparent depth is $h_2$. The value of $|h_1-h_2|$, in cm, is:
Detailed Solution
The object is 2.5 cm from each face of Q. Observer I (in P): $\frac{d'}{d}=\frac{\mu_P}{\mu_Q} \Rightarrow d'=2.5\times\frac{1}{1.25}=2$ cm $=h_1$. Observer II (in R): $d'=2.5\times\frac{1.5}{1.25}=3$ cm $=h_2$. $|h_1-h_2|=1$ cm.