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In the given figure, a diode D is connected to an external resistance R = 100 $\Omega$ and an e.m.f of 3.5 V. If the barrier potential developed across the diode is 0.5 V, the current in the circuit will be:
A
35 mA
B
30 mA
C
40 mA
D
20 mA
Detailed Solution
Potential difference across R = 3.5 − 0.5 = 3.0 V
$i = \frac{V}{R} = \frac{3}{100} = 30$ mA
$i = \frac{V}{R} = \frac{3}{100} = 30$ mA