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The input signal given to a CE amplifier having a voltage gain of 150 is $V_i = 2\cos\left(15t + \frac{\pi}{3}\right)$. The corresponding output signal will be
A
$300\cos\left(15t + \frac{4\pi}{3}\right)$
B
$300\cos\left(15t + \frac{\pi}{3}\right)$
C
$75\cos\left(15t + \frac{2\pi}{3}\right)$
D
$2\cos\left(15t + \frac{5\pi}{6}\right)$
Detailed Solution
A CE amplifier introduces a phase difference of $\pi$ between input and output.
$V_0 = A_vV_{in} = 150\times 2\cos\left(15t + \frac{\pi}{3} + \pi\right)$
$V_0 = 300\cos\left(15t + \frac{4\pi}{3}\right)$
$V_0 = A_vV_{in} = 150\times 2\cos\left(15t + \frac{\pi}{3} + \pi\right)$
$V_0 = 300\cos\left(15t + \frac{4\pi}{3}\right)$