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In a CE transistor amplifier, the audio signal voltage across the collector resistance of 2 k$\Omega$ is 2 V. If the base resistance is 1 k$\Omega$ and the current amplification of the transistor is 100, the input signal voltage is
A
10 mV
B
0.1 V
C
1.0 V
D
1 mV
Detailed Solution
Voltage gain $A_V = \frac{V_o}{V_i} = \beta\frac{R_C}{R_B}$
$\frac{2}{V_i} = 100\times\frac{2\times10^3}{1\times10^3} = 200$
$V_i = \frac{2}{200} = 0.01$ V = 10 mV
$\frac{2}{V_i} = 100\times\frac{2\times10^3}{1\times10^3} = 200$
$V_i = \frac{2}{200} = 0.01$ V = 10 mV