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Semiconductor Electronics
CE amplifier – voltage gain
1 question from 1 paper, each with its answer.
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2016 Phase II 1 question
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For CE transistor amplifier, the audio signal voltage across the collector resistance of 2 k$\Omega$ is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1 k$\Omega$, then the input signal voltage is:
$A_V = \beta R_C/R_B = 200$.
$\beta = 100$; $V_0 = 4$ V; $R_i = 10^{3}\ \Omega$; $R_0 = 2\times10^{3}\ \Omega$
$\frac{V_0}{V_i} = \beta\frac{R_0}{R_i} \Rightarrow \frac{4}{V_i} = 100\times\frac{2\times10^3}{10^3}$
$V_i = 20$ mV
