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Three masses are placed on the x-axis: 300 g at origin, 500 g at x = 40 cm and 400 g at x = 70 cm. The distance of the centre of mass from the origin is
A
30 cm
B
40 cm
C
45 cm
D
50 cm
Detailed Solution
$x_{cm} = \frac{m_1x_1 + m_2x_2 + m_3x_3}{m_1 + m_2 + m_3}$
$= \frac{300\times0 + 500\times40 + 400\times70}{300 + 500 + 400}$
$= \frac{20000 + 28000}{1200} = \frac{48000}{1200} = 40$ cm
$= \frac{300\times0 + 500\times40 + 400\times70}{300 + 500 + 400}$
$= \frac{20000 + 28000}{1200} = \frac{48000}{1200} = 40$ cm