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The moment of inertia of a uniform circular disc is maximum about an axis perpendicular to the disc and passing through
A
A
B
B
C
C
D
D
Detailed Solution
Parallel axis theorem: $I = I_{cm} + Md^2$, where d is the distance of the axis from the centre.
I is maximum for the point farthest from the centre.
B lies on the rim (d = R), while A, C and D are closer to the centre, so the moment of inertia is maximum about the axis through B.
I is maximum for the point farthest from the centre.
B lies on the rim (d = R), while A, C and D are closer to the centre, so the moment of inertia is maximum about the axis through B.