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A rod PQ of mass M and length L is hinged at end P. The rod is kept horizontal by a massless string tied to point Q as shown in figure. When string is cut, the initial angular acceleration of the rod is:
A
$\frac{2g}{3L}$
B
$\frac{3g}{2L}$
C
$\frac{g}{L}$
D
$\frac{2g}{L}$
Detailed Solution
$\tau = I\alpha \Rightarrow Mg\left(\frac{L}{2}\right) = \left(\frac{ML^2}{3}\right)\alpha$
$\alpha = \frac{3g}{2L}$
$\alpha = \frac{3g}{2L}$