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A constant torque of 100 N m turns a wheel of moment of inertia 300 kg m$^2$ about an axis passing through its centre. Starting from rest, its angular velocity after 3s is:-
A
1 rad/s
B
5 rad/s
C
10 rad/s
D
15 rad/s
Detailed Solution
$\tau=I\alpha\Rightarrow\alpha=\dfrac{\tau}{I}=\dfrac{100}{300}=\dfrac{1}{3}$ rad/sec$^2$. $\omega_i=0$; $\omega_f=\omega_i+\alpha t=0+\dfrac{1}{3}\times3=1$ rad/sec.