Looking for classes? Ksquare Career Institute, Bengaluru →
The Solid State
Body-Centred Cubic Lattice
1 question from 1 paper, each with its answer.
- question
- 1
- paper
- 1
- of The Solid State
- 16.67%
Concepts tested
- Nearest neighbour distance in BCC
All Questions
2001 AIPMT 1 question
-
In BCC, the distance between two nearest atoms will be : - (a is the edge of the unit cell)In a BCC cell, the atom at the body centre touches the atoms at the corners along the body diagonal.
Length of the body diagonal $= \sqrt{3}a$.
The nearest neighbour distance is half of the body diagonal (centre to corner): $d = \dfrac{\sqrt{3}}{2}a$.
(For BCC, the atomic radius $r = \dfrac{\sqrt{3}}{4}a$.)