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Newton's Law of Cooling
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A cup of coffee cools from $90^\circ C$ to $80^\circ C$ in $t$ minutes, when the room temperature is $20^\circ C$. The time taken by a similar cup of coffee to cool from $80^\circ C$ to $60^\circ C$ at a room temperature same at $20^\circ C$ is:A $\frac{13}{5}t$B $\frac{10}{13}t$C $\frac{5}{13}t$D $\frac{13}{10}t$
