Looking for classes? Ksquare Career Institute, Bengaluru →
1 g of water, of volume 1 cm$^3$ at $100^\circ C$, is converted into steam at same temperature under normal atmospheric pressure ($=1\times10^5$ Pa). The volume of steam formed equals 1671 cm$^3$. If the specific latent heat of vaporisation of water is 2256 J/g, the change in internal energy is,
Detailed Solution
$Q=\Delta U+P\Delta V \Rightarrow 1\times2256=\Delta U+10^5\times(1670\times10^{-6}) \Rightarrow \Delta U=2256-167=2089$ J.
