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Thermodynamics
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During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of $\frac{C_p}{C_v}$ for the gas is:$P \propto T^3$ and $PV = nRT$ give $PV^{3/2}$ = constant.
Comparing with $PV^\gamma$ = constant: $\gamma = \frac{C_p}{C_v} = \frac{3}{2}$ -
A gas is taken through the cycle A → B → C → A, as shown. What is the net work done by the gas?
Net work done = area of triangle ABC
$= \frac{1}{2}\times[(7 - 2)\times10^{-3}][(6 - 2)\times10^5] = 1000$ J